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t^2-t-100=0
We add all the numbers together, and all the variables
t^2-1t-100=0
a = 1; b = -1; c = -100;
Δ = b2-4ac
Δ = -12-4·1·(-100)
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{401}}{2*1}=\frac{1-\sqrt{401}}{2} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{401}}{2*1}=\frac{1+\sqrt{401}}{2} $
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